Stack Implementation using Single Inheritance in C++

By: Prof. Fazal Rehman Shamil

Let us see the Stack Implementation using Single Inheritance.

#include<iostream>
using namespace std;
class stackdata{
protected:
int stackarray[4],top;
stackdata()
{
top=-1;
}
~stackdata()
{
"Stack destructed!\n";
}
};
class stackfunction:public stackdata{
public:
void push(int n)
{
if (top==3)
cout<<"Stack overflow\n";
else
{
top++;
stackarray[top]=n;
}
}
void pop()
{
if (top==-1)
cout<<"Stack underflow\n";
else
{
cout<<stackarray[top]<<" popped successfully\n";
top--;
}
}
void display()
{
if(top==-1)
cout<<"Stack empty\n";
else
{
for (int i=0;i<=top;i++)
cout<<"Value "<<i+1<<": "<<stackarray[i]<<endl;
}
}
};
int main()
{
stackfunction s1;
char ch;
do{
cout<<"Press...\n"
<<"1 to push\n"
<<"2 to pop\n"
<<"3 to display\n"
<<"4 to exit\n\n";
cin>>ch;
switch(ch)
{
case '1':
int n;
cout<<"Enter element\n";
cin>>n;
s1.push(n);
break;
case '2':
s1.pop();
break;
case '3':
s1.display();
break;	
}
}
while(ch!='4');
return 0;
}

#include<iostream>

using namespace std;

class stackdata{

protected:

int stackarray[4],top;

stackdata()

{

top=-1;

}

~stackdata()

{

"Stack destructed!\n";

}

};

class stackfunction:public stackdata{

public:

void push(int n)

{

if (top==3)

cout<<"Stack overflow\n";

else

{

top++;

stackarray[top]=n;

}

void pop()

{

if (top==-1)

cout<<"Stack underflow\n";

else

{

cout<<stackarray[top]<<" popped successfully\n";

top--;

}

void display()

{

if(top==-1)

cout<<"Stack empty\n";

else

{

for (int i=0;i<=top;i++)

cout<<"Value "<<i+1<<": "<<stackarray[i]<<endl;

}

};

int main()

{

stackfunction s1;

char ch;

do{

cout<<"Press...\n"

<<"1 to push\n"

<<"2 to pop\n"

<<"3 to display\n"

<<"4 to exit\n\n";

cin>>ch;

switch(ch)

{

case '1':

int n;

cout<<"Enter element\n";

cin>>n;

s1.push(n);

break;

case '2':

s1.pop();

break;

case '3':

s1.display();

break;

}

while(ch!='4');

return 0;

}

Output

Author
Recent Posts

Prof. Fazal Rehman Shamil

CEO @ T4Tutorials.com
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