Palindrome Program in C, C++, C Plus Plus (CPP) with flow chart

How to check if a sentence is a palindrome in C++?

We need to read from left and right, if the word is the same, whether we read it from left or we read it from right, then its called palindrome.

Example of palindrome

For example, “t4tutorials” is not a palindrome but “t4t” is a palindrome.

Write a C++ program to show whether a number is a palindrome or not using a do-while loop?

Flowchart of Palindrome Program using do-while loop 

Code of Palindrome Program using do-while loop 

#include<iostream>
using namespace std;
int main()
{
	int num,r,sum=0,t;
	cout<<"enter number"<<endl;
	cin>>num;
	t=num;
	do
	{
		r=num%10;
		sum=sum*10+r;
		num=num/10;
	}
	while(num!=0);
	if(t==sum)
	{
		cout<<"The number is a palindrome:";
	}
	else
	cout<<"Number is not palidrome:";
}

Output

enter number

575

The number is a palindrome:

Suppose the input value is: 121

 

Exercise

Find the possible mistakes in the following Shamil’s Flow Table of the program to show whether a number is a palindrome or not using a do-while loop?

Flowchart of Palindrome Program using for loop 

Palindrome Program using for loop for checking the numbers as a palindrome

#include <iostream>
#include <conio.h>
using namespace std;
int main()
{
	int Input_Num;
	int Orignal_Num;
	int Reverse_Num;
	int Remainder=0;
	cout<<"Enter an Integer number:\n";
	cin>>Input_Num;
	Orignal_Num=Input_Num;
	int lengthCount = 0;
	for(; Input_Num != 0;)
	{
		Reverse_Num=Input_Num%10;
		Input_Num /= 10;
		Remainder=Remainder*10+Reverse_Num;
		Reverse_Num=Remainder;
	 } 
	 if(Orignal_Num==Reverse_Num)
	 cout<<"Number You Entered Is Palindrome";
	 else
	 cout<<"Number Is Not Palindrome!!!";
	 getch();
}

Output

Palindrome Program using for loop for checking the strings as a palindrome

#include<iostream>
 
using namespace std;
 
int main()
{
	int i,j,Number_Length,T4Tutorials_Flag=1;
	char a[20];
	
	cout<<"Enter a string:";
	cin>>a;
	
	for(Number_Length=0;a[Number_Length]!='\0';++Number_Length);
	
	for(i=0,j=Number_Length-1;i<Number_Length/2;++i,--j)
	{
		if(a[j]!=a[i])
			T4Tutorials_Flag=0;
	}
	
	if(T4Tutorials_Flag==1)
		cout<<"\nThe string is Palindrome";
	else
		cout<<"\nThe string is not Palindrome";
 
	return 0;
}

Palindrome Program in C++ using user define function

#include<stdio.h>
int checkPalindrome(int Num)
{
  int Temporary, remainder, T4Tutorials=0;
  Temporary = Num;

  while( Num!=0 )
  {
     remainder = Num % 10;
     T4Tutorials = T4Tutorials*10 + remainder;
     Num /= 10;
  }

  if ( T4Tutorials == Temporary ) return 0;
  else return 1;
}

int main()
{
  int Num;

  printf("Please! Enter the Num: ");
  scanf("%d", &Num);

  if(checkPalindrome(Num) == 0)
  printf("%d is a palindrome Num.\n",Num);
  else
  printf("%d is not a palindrome Num.\n",Num);

  return 0;
}

Output

Please! Enter the Num: 4
4 is a palindrome Num.

——————————–

Palindrome recursion C++

#include <iostream>
using namespace std;
//Writing a Recursive function to check if string is a palindrome or not
bool isPalindrome(string str, int X, int Y)
{
	// base case
	if (X >= Y)
		return true;

	// return false if mismatch happens
	if (str[X] != str[Y])
		return false;

	// move to next the pair
	return isPalindrome(str, X + 1, Y - 1);
}

int main()
{
	string str = "T4Tutorials";
	int len = str.length();

	if (isPalindrome(str, 0, len - 1))
		cout << "its Palindrome";
	else
		cout << "sorry, its Not Palindrome";

	return 0;
}

 

Palindrome Program in C

#include <conio.h>
int main()
{
	int Input_Num;
	int Orignal_Num;
	int Reverse_Num;
	int Remainder=0;
	printf("Enter an Integer Number:\n");
	scanf("%d", &Input_Num);
	Orignal_Num=Input_Num;
	int lengthCount = 0;
	for(; Input_Num != 0;)
	{
		Reverse_Num=Input_Num%10;
		Input_Num /= 10;
		Remainder=Remainder*10+Reverse_Num;
		Reverse_Num=Remainder;
	 } 
	 if(Orignal_Num==Reverse_Num)
	 printf("Number You Entered Is Palindrome");
	 else
	 printf("Number Is Not Palindrome!!!");
	getch();
}

Output