Write a program in C++ to convert a decimal number into binary without using an array.
| INTEGER PART | QUOTIENT | REMAINDER | REMAINDER IN QUOTIENT |
| 4/2 | 2 | 0 | 0 |
| 2/2 | 1 | 0 | 0 |
| 1/2 | 0 | 1 | 1 |
(4)10 = (100)2
Flowchart of decimal number into binary without using an array
C++ code of decimal number into binary using do-while loop
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 |
#include <iostream> using namespace std; int main() { int i,j,n,binaryn=0,decimaln=n; cout<<"enter decimal no:"; cin>>n; i=1; j=n; do { binaryn=binaryn+(n%2)*i; i=i*10; n=n/2; j=j/2; } while(j>0); cout<<"the binary no is:"<<binaryn; } |
Output
enter decimal no: 7
the binary no is: 11
Excercise
Find the possible mistakes in the following Shamil’s Flow Table of the program of decimal number into binary using a do-while loop.
| Loop
|
Condition | What lines will execute | Actual work
|
| 1 time
J=4 4>0
|
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16
|
J=n,n=4,i=1,bin=0
Bin=0+(4%2)*1=0 i=1*10=10 n=4/2=2 |
|
| 2 time
J=4 J=j/2=4/2 J=2 2>0
|
True | 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16
17, 10, 11, 12, 13, 14, 15, 16
|
Bin=0+(2%2)*10=0
i=10*10=100 n=2/2=1
|
| 3 time
J=2 J=2/2 J=1 1>0
|
True |
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16 17, 10, 11, 12, 13, 14, 15, 16 17,10,11,12,13,14,15,16
|
Bin=0+(1%2)*100=100
i=100*10=1000 n=1/2=0
|
| 4 time
J=1 J=1/2 J=0 0>0
|
False
|
1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16
17, 10, 11, 12, 13, 14, 15, 16 17,18, 19
|
Print binary =100 |
C++ code of decimal number into binary using while loop
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 |
#include <iostream> using namespace std; int main() { int n, i, j, binary=0,num; cout<<"Convert Decimal to Binary:"<<endl; cout<<"-------------------------"<<endl; cout<<"Enter a number : "; cin>>n; num=n; i=1; j=n; while(j>0) { binary=binary+(n%2)*i; i=i*10; n=n/2; j=j/2; } cout<<"The Binary of "<<num<<" is = "<<binary; } |
Decimal number into binary using for loop in C++
Write a program in C++ to convert a decimal number into binary number using for loop.
|
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 |
#include <iostream> using namespace std; int main() { int T4Tutorials[10], n, i; cout<<"Please Enter the number to convert: "; cin>>n; for(i=0; n>0; i++) { T4Tutorials[i]=n%2; n= n/2; } cout<<"Binary of the given number= "; for(i=i-1 ;i>=0 ;i--) { cout<<T4Tutorials[i]; } } |
Output
Please Enter the number to convert: 8
Binary of the given number= 1000
CEO @ T4Tutorials.com
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I welcome to all of you if you want to discuss about any topic. Researchers, teachers and students are allowed to use the content for non commercial offline purpose. Further, You must use the reference of the website, if you want to use the partial content for research purpose.
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