Leap Year in Python – T4Tutorials.com

Write a Program in Python to check if a Year is Leap Year or not.

#Starting with a Default function to implement conditions to find a leap year  
def CheckLeap(Year):  
  # This part will check that the given year is leap year  
  if((Year % 400 == 0) or  
     (Year % 100 != 0) and  
     (Year % 4 == 0)):   
    print("Congratulations! Given Year is a leap Year");  
  # Else it is not a leap year  
  else:  
    print ("Sorry! Given Year is not a leap Year")  
# Getting an input year from user  
Year = int(input("Please Enter the number: "))  
# Display the result  
CheckLeap(Year)

#Starting with a Default function to implement conditions to find a leap year

def CheckLeap(Year):

# This part will check that the given year is leap year

if((Year % 400 == 0) or

(Year % 100 != 0) and

(Year % 4 == 0)):

print("Congratulations! Given Year is a leap Year");

# Else it is not a leap year

else:

print ("Sorry! Given Year is not a leap Year")

# Getting an input year from user

Year = int(input("Please Enter the number: "))

# Display the result

CheckLeap(Year)

Output Please Enter the number: 234 Sorry! Given Year is not a leap Year Flowchart of leap year or not by using an if-else statement

Leap Year in Python
By: Prof. Dr. Fazal Rehman | Last updated: February 3, 2024

Related Posts:

Leave a Comment