Write a C++ program to check whether a year is a leap year or not by Using an if-else statement.
Flowchart of leap year or not by using an if-else statement
C++ Source Code of leap year or not with the help of if-else statement
#include<iostream>
using namespace std;
int main()
{
int year;
cout<<"Enter year to check wather it is leap year or not"<<endl;
cin>>year;
if(year%4==0)
{
cout<<year<<" "<<"is a leap year ";
}
else
{
cout<<year<<" "<<"Is not leap year";
}
return 0;
}
Output
Enter a year to check whether it is a leap year or not
4
4 is a leap year
SFT (Shamil’s Flow Table )
Are you interested to Read about SFT(Shamil’s Flow Table)?

C++ Exercise | If else Statement
- calculate the bill
- character is small, capital or a special character
- a number is even or odd
- 0 is a positive or negative number
- a positive and negative number
- Enter Range of numbers and replaced them
- a greater number among three numbers
- Armstrong Number
- ASCII code
- Find the Maximum value program in C++ (C Plus Plus).
- maximum number
- Maximum Number between two numbers
- Student Grade
- the number is divisible by 11 or 5 or not
- Triangle
- a triangle is an equilateral, isosceles or scalene
- Leap year
- character is an alphabet or not
- Grade Percentage
- character is an alphabet, digit, or special character
- character is an uppercase or lowercase.
- Weekdays
- a prime or composite number
- hours and minutes as AM or PM
- swap the values of two numbers
- update even to odd
- Profit Loss
- centimeter into meter and kilometer
- Triangle
- Salary
- Even odd with goto statement.
- area of the circle

