Armstrong Number Program in C++, C Plus Plus CPP with Flowchart

Armstrong Number Program in C++, C Plus Plus CPP with Flowchart.

An Armstrong number of three digits is an integer in such a way that the sum of the cubes of all its digits is equal to the number itself.

Example of Armstrong number

371 is an Armstrong number since (3*3*3 =27)+ (7*7*7=343) + (1*1*1=1) =(27+343+1)= 371.
Armstrong number 1: 0
Armstrong number 2: 1
Armstrong number 3: 153 since (1*1*1=1) + (5*5*5=125) + (3*3*3=27)= (1+125+27)
Armstrong number 4: 370
Armstrong number 5: 371
Armstrong number 6: 407

Flowchart of the program of Armstrong Number with Flowchart

Armstrong Number Program in C++, C Plus Plus CPP Flow chart — **Figure:** Armstrong Number Program in C++, C Plus Plus CPP with Flowchart.

Armstrong Number Program in C++ using While Loop

Let’s see the programming example of Armstrong Number Program in C++ using While Loop”.

#include<iostream>
#include<conio.h>
using namespace std;

int main()
{
int Armstrong=0;
int o;
int y;
int number; 
cout<<"Enter Any number for Digits Armstrong: ";
 cin>>number;
y=number;
while(number>0)
{
o=number%10;
number=number/10;
Armstrong=Armstrong+o*o*o;
}
if(Armstrong==y)
{
cout<<"this is Armstrong number";
}
else
{
cout<<"this is not a Armstrong number";
}
getch();
}

Output

Armstrong Number Flow chart — **Figure:** Armstrong Number Flowchart.

Armstrong Number Program in C++ using For Loop

Let’s see the programming example of Armstrong Number Program in C++ using For Loop”.

#include<iostream>
using namespace std;
int main()
{
	int Armstrong=0;
	int a;
	int b;
	int d;
	int num;
	cout<<"Enter any no for digits:";
	cin>>num;
	d=num;
	num=0;
		for(num=0;num>0;num++)
	{
		a=num%10;
		num=num/10;
		Armstrong=Armstrong+a*a*a;
	}

	if(Armstrong==d)
	{
	cout<<"This is Armstrong no:";	
	}
	else
	{
		cout<<"This is not an Armstrong:";
	}
}

Armstrong Number Program in C++ using User Define Functions

Let’s see the programming example of Armstrong Number Program in C++ using user define funcitons”.

#include<iostream>
using namespace std;
int number(int);
int main()
{
	int Armstrong=0;
	int a;
	int b;
	int c;
	int d;
	int num;
	int n=number(num);
	d=n;
	
	while(n>0)
	{
	a=n%10;
	n=n/10;
	Armstrong=Armstrong+a*a*a;
	}
	if(Armstrong==d)
	{
		cout<<"This is Armstrong no:";
	}
	else
	{
		cout<<"This is not an Armstrong";
	}
}
	int number(int num)
	{
	cout<<"Enter any no for digit armstrog::";
	cin>>num;
	return num;
	}

Armstrong Number Program in C

#include<stdio.h>

int main()
{
int Armstrong=0;
int o;
int q;
int w;
int y;
int number; 
printf("Enter Any number for Digits Armstrong: ");
scanf("%d", &number);
y=number;
while(number>0)
{
o=number%10;
number=number/10;
Armstrong=Armstrong+o*o*o;
}
if(Armstrong==y)
{
printf("this is Armstrong number");
}
else
{
Printf("this is not a Armstrong number");
}
getch();
}

Output