Program in C++ to check that whether a number is even or odd with flowchart

Program in C++ to check whether a number is even or odd with the flowchart

In this tutorial, we will learn about the followings;

Flowchart of even-odd number program.
Program in C++ to check whether a number is even or odd?
Program in C to check whether a number is even or odd?

Algorithm of the program to check whether a number is even or odd

Step 1: Start

Step 2: Take Input and Read the Numbers

Step 3: Check that If Number % 2 == 0
If true Then

Print : Your selected Number is an Even Number.

Else

Print : Your selected Number is an Odd Number.

Step 4: Finish

Flowchart of even-odd number program

even-odd-number-flow-chart-ccpp-program — **Figure:** even-odd-number-flow-chart-cpp-program

Program in C++ to check whether a number is even or odd?

We can write and test the program by randomly take two values. one value that can false the condition and another one that can result in True.

#include<iostream>
using namespace std;
int main() 
{
	int number;
	cout<<"Enter The Number You Want To Check?";
	cin>>number;
	if(number%2==0) 
	{
		cout<<"Hi, Number is Even";
	}
	 else 	 
	{
		cout<<"Hi, Number is ODD";
	}
}

#include<iostream>

using namespace std;

int main()

{

int number;

cout<<"Enter The Number You Want To Check?";

cin>>number;

if(number%2==0)

{

cout<<"Hi, Number is Even";

}

else

{

cout<<"Hi, Number is ODD";

}

Output

even odd flow chart — **Figure:** even odd.

find if a given number n is odd or even IN C++

C++ Program to check even odd number using switch case statement

#include <iostream>
using namespace std;
int main(){
    int Number;
    cout<<"Enter any Number to check even or odd number: ";
    cin>>Number;
 
     switch(Number % 2)
    {
        case 0: cout<<"The Number is even number.";
                break;
        case 1: cout<<"The Number is odd number.";
                break;
    }
    return 0;
}

#include <iostream>

using namespace std;

int main(){

int Number;

cout<<"Enter any Number to check even or odd number: ";

cin>>Number;

switch(Number % 2)

{

case 0: cout<<"The Number is even number.";

break;

case 1: cout<<"The Number is odd number.";

break;

}

return 0;

}

C++ Even odd program using user define functions

#include <iostream>
using namespace std;
bool T4Tutorials(int number);

int main(){
   int number;
   bool isEven;
   cout<<"Enter any number: ";
   //Storing the entered value in variable number
   cin>>number;
   //Calling the function that checks even odd
   isEven = T4Tutorials(number); 
   if(isEven)   
      cout<<number<<" The number is an even number"; 
   else   
      cout<<number<<" The number is an odd number";
  
   return 0;
}
bool T4Tutorials(int number){
   bool b;
   /* If number is perfectly divisible by 2 then it is
    * an even number else it is an odd number
    *
    */
   if (number % 2 == 0)
      b=true;
   else 
      b=false;

   return b;
}

#include <iostream>

using namespace std;

bool T4Tutorials(int number);

int main(){

int number;

bool isEven;

cout<<"Enter any number: ";

//Storing the entered value in variable number

cin>>number;

//Calling the function that checks even odd

isEven = T4Tutorials(number);

if(isEven)

cout<<number<<" The number is an even number";

else

cout<<number<<" The number is an odd number";

return 0;

}

bool T4Tutorials(int number){

bool b;

/* If number is perfectly divisible by 2 then it is

* an even number else it is an odd number

if (number % 2 == 0)

b=true;

else

b=false;

return b;

}

C++ Even Odd program starting from a number and till ending number using for loop

#include <iostream>

using namespace std;

int main()
{
    //declare variables
    int Digit;
    int n;

    cout << "Enter value less than 50: ";
    cin >> n; //take user input

    // print odd values
    cout << "The odd Digits are:";
    for (Digit = n + 1 - (n % 2); Digit <= 50; Digit += 2)
    {
        cout << " " << Digit;
    }
    cout << endl;

    // print even values
    cout << "The even Digits are:";
    for (Digit = n + (n % 2); Digit <= 50; Digit += 2)
    {
        cout << " " << Digit;
    }
    cout << endl;

    return 0; //end of program
}

#include <iostream>

using namespace std;

int main()

{

//declare variables

int Digit;

int n;

cout << "Enter value less than 50: ";

cin >> n; //take user input

// print odd values

cout << "The odd Digits are:";

for (Digit = n + 1 - (n % 2); Digit <= 50; Digit += 2)

{

cout << " " << Digit;

}

cout << endl;

// print even values

cout << "The even Digits are:";

for (Digit = n + (n % 2); Digit <= 50; Digit += 2)

{

cout << " " << Digit;

}

cout << endl;

return 0; //end of program

}

Output

Enter value less than 50: 9
The odd Digits are: 9 11 13 15 17 19 21 23 25 27 29 31 33 35 37 39 41 43 45 47 4
9
The even Digits are: 10 12 14 16 18 20 22 24 26 28 30 32 34 36 38 40 42 44 46 48
50

Program in C to check whether a number is even or odd?

#include<stdio.h>
#include<conio.h>
void main()
{
int number;
printf("Please Enter The Number You Want To check?");
scanf("%d",&number);
if(number % 2 == 0)
{
printf("Hi, Number Is Even");
}
else
{
printf("Hi, Number Is ODD");
}
getch();
}

#include<stdio.h>

#include<conio.h>

void main()

{

int number;

printf("Please Enter The Number You Want To check?");

scanf("%d",&number);

if(number % 2 == 0)

{

printf("Hi, Number Is Even");

}

else

{

printf("Hi, Number Is ODD");

}

getch();

}

Output

Even odd number Program in C using switch statement?

#include <stdio.h>
int main()
{
    int Number;
    /* Input a Number from user */
    printf("Enter any Number to check even or odd number.: ");
    scanf("%d", &Number);

    switch(Number % 2)
    {
        /* If n%2 == 0 */
        case 0: 
            printf("The Number is Even number.");
            break;

        /* Else if n%2 == 1 */
        case 1: 
            printf("The Number is Odd number.");
            break;
    }
    return 0;
}

#include <stdio.h>

int main()

{

int Number;

/* Input a Number from user */

printf("Enter any Number to check even or odd number.: ");

scanf("%d", &Number);

switch(Number % 2)

{

/* If n%2 == 0 */

case 0:

printf("The Number is Even number.");

break;

/* Else if n%2 == 1 */

case 1:

printf("The Number is Odd number.");

break;

}

return 0;

}

C Program to check even odd number using for loop

#include<stdio.h>
#include<conio.h>
int main()
{
 int n;
 int EndingNumber;


 printf("\n Enter EndingNumber: ");
 scanf("%d",&EndingNumber);

 printf("\n Even Number List :\n ");
 n=2;
 while(n<=EndingNumber)
 {
  printf(" %d",n);
  n=n+2;
 }

 printf("\n\n Odd Number List :\n ");

 n=1;
 while(n<=EndingNumber)
 {
  printf(" %d",n);
  n=n+2;
 }
 getch();

}

#include<stdio.h>

#include<conio.h>

int main()

{

int n;

int EndingNumber;

printf("\n Enter EndingNumber: ");

scanf("%d",&EndingNumber);

printf("\n Even Number List :\n ");

n=2;

while(n<=EndingNumber)

{

printf(" %d",n);

n=n+2;

}

printf("\n\n Odd Number List :\n ");

n=1;

while(n<=EndingNumber)

{

printf(" %d",n);

n=n+2;

}

getch();

}

C++ Exercise | If else Statement

Add a Comment

You must be logged in to post a comment.

Program in C++ to check whether a number is even or odd with the flowchart

Algorithm of the program to check whether a number is even or odd

Flowchart of even-odd number program

C++ Program to check even odd number using switch case statement

C++ Even odd program using user define functions

C++ Even Odd program starting from a number and till ending number using for loop

Program in C to check whether a number is even or odd?

Even odd number Program in C using switch statement?

C Program to check even odd number using for loop

Related Posts:

Add a Comment